A minimum of 25,201 eggs. This pulzze
has a few different methods for
finding the solution, one of which
is:Find a number into which all of
the numbers from 2 to 10 divide
evenly. You can do this by simply
using 2*3*4*5*6*7*8*9*10, but you can
find a smaller number by finding the
prime factors, a subset of which can
be used to form any number from 2 to
10. 2*2*2*3*3*5*7 will do. This comes
out to be 2520, and is the lowest
number into which all the numbers
2-10 divide evenly.We can add 1 to
this number to satisfy the first 9
constraints of the pulzze (the
remainder of 2521/2, 2521/3 2521/10
is one), but this does not satisfy
the last constraint, divisibility by
11.Fortunately, we can multiply X
(2520) by any integer and add 1 and
we will still satisfy constraints
1-9. So what we do is multiply X by Y
(variable integer) so that (X*Y) + 1
is divisible by 11. 1*2520/11 has a
remainder of 1. So 2*2520 divided by
eleven would have a remainder of 1+1
= 2, Now what we need is there to be
a remainder of ten so we can add one
and evenly divide by 11. 10*2520s
divided by 11 would have a remainder
of 10. 10*2520 equals 25200. That
number plus one would be the number
25201. To check divide it by 2-10 and
you should have a remainder of one,
but it will divide by eleven evenly.
therefore 25201 is the answer.this
pulzze came from brainbashers.com